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PBDS Code Generator

Generate ready-to-paste C++ Order Statistics Tree code. Configure key type, comparator, and duplicate support. One-click copy.

How to Use

  1. 1Open PBDS Code Generator above. No signup or installation needed.
  2. 2Type or paste your input. Everything runs locally in your browser — nothing leaves your device.
  3. 3See results instantly. Hit Copy to grab the output.
  4. 4Star the tool to save it to Favorites for quick access next time.

Frequently Asked Questions

Is PBDS Generator free?

Yes, completely free. No sign-up, no credit card, no usage limits.

Do you store my data?

Never. Everything runs 100% in your browser. Nothing is uploaded to any server.

Does it work on mobile?

Yes. All tools are fully responsive and work on phones, tablets, and desktops.

Configure Your PBDS Tree

Generated C++ Code

// PBDS Order Statistics Tree — generated by UtilityToolsLab
// Requires: GCC with policy-based headers
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

// Tree type alias
typedef tree<
    int,
    null_type,
    less<int>,
    rb_tree_tag,
    tree_order_statistics_node_update
> ordered_set;

// Wrapper with helper methods
struct OST {
    ordered_set tree;
    void insert(int val) { tree.insert(val); }

    // find_by_order: k-th element (0-indexed)
    int find_by_order(int k) {
        return *tree.find_by_order(k);
    }

    // order_of_key: number of elements strictly less than val
    int order_of_key(int val) { return tree.order_of_key(val); }

    void erase(int val) { tree.erase(val); }
    int size() { return tree.size(); }
    bool empty() { return tree.empty(); }
};

// Usage example:
// OST ost;
// ost.insert(5); ost.insert(3); ost.insert(7);
// cout << ost.order_of_key(5) << endl;  // 1 (one element < 5)
// cout << ost.find_by_order(0) << endl; // 3 (smallest)

Key Operations Reference

ost.insert(x)Insert element x
ost.order_of_key(x)# elements strictly < x
ost.find_by_order(k)k-th element (0-indexed)
ost.erase(x)Remove one occurrence of x